The matching operations can have various modifiers, some of which relate to the interpretation of the regular expression inside. These are:
These are usually written as ``the /x
modifier'', even though the delimiter
in question might not actually be a slash. In fact, any of these
modifiers may also be embedded within the regular expression itself using
the new (?...)
construct. See below.
The /x
modifier itself needs a little more explanation. It tells
the regular expression parser to ignore whitespace that is not
backslashed or within a character class. You can use this to break up
your regular expression into (slightly) more readable parts. The #
character is also treated as a metacharacter introducing a comment,
just as in ordinary Perl code. Taken together, these features go a
long way towards making Perl 5 a readable language. See the C comment
deletion code in
the perlop manpage
.
In particular the following metacharacters have their standard egrep-ish meanings:
By default, the ``^'' character is guaranteed to match only at the beginning of the string, the ``$'' character only at the end (or before the newline at the end) and Perl does certain optimizations with the assumption that the string contains only one line. Embedded newlines will not be matched by ``^'' or ``$''. You may, however, wish to treat a string as a multi-line buffer, such that the ``^'' will match after any newline within the string, and ``$'' will match before any newline. At the cost of a little more overhead, you can do this by using the /m modifier on the pattern match operator. (Older programs did this by setting $* , but this practice is deprecated in Perl 5.)
To facilitate multi-line substitutions, the ``.'' character never matches a
newline unless you use the /s
modifier, which tells Perl to pretend
the string is a single line--even if it isn't. The /s
modifier also
overrides the setting of
$*
, in case you have some (badly behaved) older
code that sets it in another module.
The following standard quantifiers are recognized:
(If a curly bracket occurs in any other context, it is treated
as a regular character.) The ``*'' modifier is equivalent to {0,}
, the ``+''
modifier to {1,}
, and the ``?'' modifier to {0,1}
. n and m are limited
to integral values less than 65536.
By default, a quantified subpattern is ``greedy'', that is, it will match as many times as possible without causing the rest pattern not to match. The standard quantifiers are all ``greedy'', in that they match as many occurrences as possible (given a particular starting location) without causing the pattern to fail. If you want it to match the minimum number of times possible, follow the quantifier with a ``?'' after any of them. Note that the meanings don't change, just the ``gravity'':
Since patterns are processed as double quoted strings, the following also work:
In addition, Perl defines the following:
Note that \w
matches a single alphanumeric character, not a whole
word. To match a word you'd need to say \w+
. You may use \w
,
\W
, \s
, \S
, \d
and \D
within character classes (though not
as either end of a range).
Perl defines the following zero-width assertions:
A word boundary (\b
) is defined as a spot between two characters that
has a \w
on one side of it and and a \W
on the other side of it (in
either order), counting the imaginary characters off the beginning and
end of the string as matching a \W
. (Within character classes \b
represents backspace rather than a word boundary.) The \A
and \Z
are
just like ``^'' and ``$'' except that they won't match multiple times when the
/m
modifier is used, while ``^'' and ``$'' will match at every internal line
boundary.
When the bracketing construct ( ... )
is used, \<digit> matches the
digit'th substring. Outside of the pattern, always use ``$'' instead of ``\''
in front of the digit. (The \<digit> notation can on rare occasion work
outside the current pattern, this should not be relied upon. See the
WARNING below.) The scope of $<digit> (and
$`
, $&
, and $')
extends to the end of the enclosing BLOCK or eval string, or to the next
successful pattern match, whichever comes first. If you want to use
parentheses to delimit subpattern (e.g. a set of alternatives) without
saving it as a subpattern, follow the ( with a ?.
You may have as many parentheses as you wish. If you have more than 9 substrings, the variables $10, $11, ... refer to the corresponding substring. Within the pattern, \10, \11, etc. refer back to substrings if there have been at least that many left parens before the backreference. Otherwise (for backward compatibilty) \10 is the same as \010, a backspace, and \11 the same as \011, a tab. And so on. (\1 through \9 are always backreferences.)
$+
returns whatever the last bracket match matched. $&
returns the
entire matched string. (
$0
used to return the same thing, but not any
more.)
$`
returns everything before the matched string.
$'
returns
everything after the matched string. Examples:
You will note that all backslashed metacharacters in Perl are
alphanumeric, such as \b
, \w
, \n
. Unlike some other regular expression
languages, there are no backslashed symbols that aren't alphanumeric.
So anything that looks like \\, \(, \), \<, \>, \{, or \} is always
interpreted as a literal character, not a metacharacter. This makes it
simple to quote a string that you want to use for a pattern but that
you are afraid might contain metacharacters. Simply quote all the
non-alphanumeric characters:
You can also use the built-in quotemeta() function to do this. An even easier way to quote metacharacters right in the match operator is to say
Perl 5 defines a consistent extension syntax for regular expressions. The syntax is a pair of parens with a question mark as the first thing within the parens (this was a syntax error in Perl 4). The character after the question mark gives the function of the extension. Several extensions are already supported:
/x
switch is used to enable
whitespace formatting, a simple #
will suffice.
is like
but doesn't spit out extra fields.
/\w+(?=\t)/
matches a word followed by a tab, without including the tab in $&
.
/foo(?!bar)/
matches any occurrence of ``foo'' that isn't followed by ``bar''. Note
however that lookahead and lookbehind are NOT the same thing. You cannot
use this for lookbehind: /(?!foo)bar/
will not find an occurrence of
``bar'' that is preceded by something which is not ``foo''. That's because
the (?!foo)
is just saying that the next thing cannot be ``foo''--and
it's not, it's a ``bar'', so ``foobar'' will match. You would have to do
something like /(?foo)...bar/
for that. We say ``like'' because there's
the case of your ``bar'' not having three characters before it. You could
cover that this way: /(?:(?!foo)...|^..?)bar/
. Sometimes it's still
easier just to say:
(?i)
at the front of the
pattern. For example:
Any single character matches itself, unless it is a metacharacter
with a special meaning described here or above. You can cause
characters which normally function as metacharacters to be interpreted
literally by prefixing them with a ``\'' (e.g. ``\.'' matches a ``.'', not any
character; ``\\'' matches a ``\''). A series of characters matches that
series of characters in the target string, so the pattern blurfl
would match ``blurfl'' in the target string.
You can specify a character class, by enclosing a list of characters
in []
, which will match any one of the characters in the list. If the
first character after the ``['' is ``^'', the class matches any character not
in the list. Within a list, the ``-'' character is used to specify a
range, so that a-z
represents all the characters between ``a'' and ``z'',
inclusive.
Characters may be specified using a metacharacter syntax much like that
used in C: ``\n'' matches a newline, ``\t'' a tab, ``\r'' a carriage return,
``\f'' a form feed, etc. More generally, \nnn, where nnn is a string
of octal digits, matches the character whose ASCII value is nnn.
Similarly, \xnn, where nn are hexidecimal digits, matches the
character whose ASCII value is nn. The expression \cx matches the
ASCII character control-x. Finally, the ``.'' metacharacter matches any
character except ``\n'' (unless you use /s
).
You can specify a series of alternatives for a pattern using ``|'' to
separate them, so that fee|fie|foe
will match any of ``fee'', ``fie'',
or ``foe'' in the target string (as would f(e|i|o)e
). Note that the
first alternative includes everything from the last pattern delimiter
(``('', ``['', or the beginning of the pattern) up to the first ``|'', and
the last alternative contains everything from the last ``|'' to the next
pattern delimiter. For this reason, it's common practice to include
alternatives in parentheses, to minimize confusion about where they
start and end. Note however that ``|'' is interpreted as a literal with
square brackets, so if you write [fee|fie|foe]
you're really only
matching [feio|]
.
Within a pattern, you may designate subpatterns for later reference by
enclosing them in parentheses, and you may refer back to the nth
subpattern later in the pattern using the metacharacter \n.
Subpatterns are numbered based on the left to right order of their
opening parenthesis. Note that a backreference matches whatever
actually matched the subpattern in the string being examined, not the
rules for that subpattern. Therefore, (0|0x)\d*\s\1\d*
will
match ``0x1234 0x4321'',but not ``0x1234 01234'', since subpattern 1
actually matched ``0x'', even though the rule 0|0x
could
potentially match the leading 0 in the second number.
This is grandfathered for the RHS of a substitute to avoid shocking the
sed addicts, but it's a dirty habit to get into. That's because in
PerlThink, the right-hand side of a
s///
is a double-quoted string. \1
in
the usual double-quoted string means a control-A. The customary Unix
meaning of \1
is kludged in for
s///
. However, if you get into the habit
of doing that, you get yourself into trouble if you then add an /e
modifier.
Or if you try to do
You can't disambiguate that by saying \{1}000
, whereas you can fix it with
${1}000
. Basically, the operation of interpolation should not be confused
with the operation of matching a backreference. Certainly they mean two
different things on the left side of the
s///
.